一定量的氫氣在氯氣中燃燒，所得混合物用100mL 3.00mol/L的NaOH溶液(密度放1.12)

【專家解說】：n(NaOH)=0.1×3.=0.3mol NaOH溶液質量數(shù) =100%x0.3mol×40g/mol / (100ml×1.12g/mL) =10.7% NaClO說明燃燒氯氣量燃燒剩余氯氣 設氫氣xmol 氯氣ymol H2+Cl2===2HCl 1 1 2 x x 2x HCL+NaOH=H2O+NaCl 1 1 1 2x 2x 2x Cl2+2NaOH=NaCl+NaClO+H2O 1 2 1 1 y-x 2y-2x y-x y-x 根據已知 2x+ 2y-2x=0.03 y-x=0.05 y=0.15mol x=0.1mol Cl-物值量=2x+y-x=x+y=0.25mol 根據程式用元素守恒Na+守恒解答 根據鈉離守恒Na+共0.3mol鈉離其0.05molNaClO 所NaCl0.25mol, Cl- 物質量0.25mol